88+19n+n^2=0

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Solution for 88+19n+n^2=0 equation: 



88+19n+n^2=0

a = 1; b = 19; c = +88;
Δ = b2-4ac
Δ = 192-4·1·88
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$


$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-3}{2*1}=\frac{-22}{2}
=-11
$


$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+3}{2*1}=\frac{-16}{2}
=-8
$

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